For simple question, interviewer tends to ask you questions with constraints - solve it without any built in or library funciton
这是锻炼你solving problem with constraints的能力;
trick: log可以用来获取number of digit
$$ \begin{align*} log_{10}1 = 0\ log_{10}2 = 0.301\ log_{10}9 = 0.954\ log_{10}10 = 1\ log_{10}99 = 1.995\ log_{10}100 = 2\ \dots\ log_{10}1000 = 3\
\end{align*} $$
Algorithm
- get the number of digits in
nfor calculatingfloor(log10n) + 1 - call
getSumOfKthPowerDigits()by using the digit rolling trick withn%10andn/10